If cosecθ = 3x cotθ = \(\frac{3}{x}\)  (x\(\neq \)0°) find, 6(x2-\(\frac{1}{x^2}\))

\(\frac{2}{3}\) 1 \(\frac{3}{4}\) \(\frac{1}{2}\)

\(\frac{2}{3}\)

cosec2θ - cot2θ = 1  (we know) (3x)2 - (\(\frac{3}{x}\))2 = 1 9x2-\(\frac{9}{x^2}\) = 1 x2-\(\frac{1}{x^2}\) = \(\frac{1}{9}\) Put in find 6(\(\frac{1}{9}\)) = \(\frac{2}{3}\)