The magnetic field produced at the centre of circular loop of diameter 4 cm is $6.28 × 10^{-5}T$. The current required to flow in the loop is: $(μ_0=4π×10^{-7} NA^{-2})$
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 2 A
The magnetic field (B) at the center of the circular loop carrying current (I) is -
$B=\frac{μ_0}{2R}$
where,
$B = 6.28×10^{-5}T$ [given]
R, Radius of circular loop = $\frac{diameter}{2}=0.02m$
$∴I=\frac{2BR}{μ_0}=\frac{2×(6.28×10^{-5})×0.02}{4π×10^{-7}}$
$≃2.0A$