The magnetic field produced at the centre of circular loop of diameter 4 cm is $6.28 × 10^{-5}T$. The current required to flow in the loop is: $(μ_0=4π×10^{-7} NA^{-2})$

2 A

The correct answer is Option (3) → 2 A

The magnetic field (B) at the center of the circular loop carrying current (I) is -

$B=\frac{μ_0}{2R}$

where,

$B = 6.28×10^{-5}T$ [given]

R, Radius of circular loop = $\frac{diameter}{2}=0.02m$

$∴I=\frac{2BR}{μ_0}=\frac{2×(6.28×10^{-5})×0.02}{4π×10^{-7}}$

$≃2.0A$