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Home Questions ZPEVQ2AY2T
Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Linear Programming

Question:
Resource

 Found

 Requirement units
I(x kg) II(y kg)

Calcium (units .kg)

Vitamin (units /kg

3

4

2

1

9

5
Cost (Rs/kg) 40 60  

Formulate the L.P.P to minimize the cost

Options:

Min $z=40x+60y$

$3x+2y≥9$

$4x+y ≥5$

$x,y ≥ 0$

Min $z=9x+5y$

$3x+2y ≥ 40$

$4x+y ≥ 60$

$x, y ≥ 0$

Min $z= 40 x+ 60 y $

$3x+ 2y ≤9$

$4x +y ≤ 10$

$x, y ≤0$

Min $z=9x + 5y$

$3x+ 2y ≤ 40$

$4x+y ≥60$

$x, y ≥0$

Correct Answer:

Min $z=40x+60y$

$3x+2y≥9$

$4x+y ≥5$

$x,y ≥ 0$

Explanation:

The correct answer is Option (3)

function $Z = 40x+60y$ (optimize/minimize cost)

constraints $x,y≥0$

minimum required of Calcium = 9

$⇒3x+2y≥9$

minimum required of vitamin = 5

$⇒4x+y≥5$

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