The temperature inside a refrigerator is t2°C and the room temperature is t1°C. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be :
Answer & explanation
Correct answer: option 2
K = \(\frac{Q_2}{W}\)
= \(\frac{1}{\frac{t_1}{t_2}-1}\)
Q2 = \(\frac{t_2 W}{t_1 - t_2}\)
Q1 = W + Q2
= \(\frac{t_1 + 273}{t_1 - t_2}\)