The sides AB and AC of ΔABC are produced to points D and E, respectively. The bisectors of ∠CBD and ∠BCE meet at P. If ∠A = 88o, then measure of ∠P is :
Answer & explanation
Correct answer: option 1
As shown in the figure,
P is the point where bisectors of the \(\angle\)DBC and \(\angle\)BCE meet.
\(\angle\)P = \(\frac{1}{2}\)(\({180}^\circ\) - \(\angle\)BAC)
\(\angle\)P = \(\frac{1}{2}\)(\({180}^\circ\) - \({88}^\circ\))
\(\angle\)P = \({46}^\circ\)
Therefore, value of \(\angle\)P is \({46}^\circ\)