In the given diagram, the direction of current is given. Due to the presence of the current carrying wire, the loop ABCD will be |
stationary attracted towards the wire repelled by the wire rotating around the wire |
repelled by the wire |
The correct answer is Option (3) → repelled by the wire The straight wire with current $i_1$ produces concentric magnetic field lines (right-hand rule). On the nearer side (AD), current $i_2$ flows upward. Since $i_1$ is downward, the currents are opposite, producing a repulsive force. On the farther side (BC), current is parallel to $i_1$ (both downward in effect), giving an attractive force, but it is weaker due to larger distance. Hence the net effect on loop ABCD is that it is repelled by the wire. Answer: Repelled by the wire |