Find the interval for which the function $f(x) = \cot^{-1}x + x$ increases. |
$(-\infty, 0)$ $(0, \infty)$ $(-\infty, \infty)$ $(-\infty, -1) \cup (1, \infty)$ |
$(-\infty, \infty)$ |
The correct answer is Option (3) → $(-\infty, \infty)$ ## Given, $f(x) = \cot^{-1}x + x$ $f'(x) = \frac{-1}{1+x^2} + 1 = \frac{-1+1+x^2}{1+x^2}$ $= \frac{x^2}{1+x^2} \geq 0$ for all $x \in \mathbb{R}$. $∴f$ increases for $(-\infty, \infty)$. |