The side of an equilateral triangle is 12 cm. What is the radius of the circle circumscribing this equilateral triangle?
Answer & explanation
Correct answer: option 2
We know that,
The radius of a circle circumscribing an equilateral triangle = \(\frac{side}{\sqrt {3}}\)
We have,
The side of an equilateral triangle = 12 cm.
According to the question,
Radius of the circle = \(\frac{12}{\sqrt {3}}\) = \(\frac{(4 × 3)}{\sqrt {3}}\) = 4\(\sqrt {3}\)