The side of an equilateral triangle is 12 cm. What is the radius of the circle circumscribing this equilateral triangle?

$4\sqrt{3}$cm

We know that,

The radius of a circle circumscribing an equilateral triangle = \(\frac{side}{\sqrt {3}}\) 

We have,

The side of an equilateral triangle = 12 cm.

According to the question,

Radius of the circle = \(\frac{12}{\sqrt {3}}\)  = \(\frac{(4 × 3)}{\sqrt {3}}\) = 4\(\sqrt {3}\)