If $A=\begin{pmatrix}-2 & 1\\3& 2\end{pmatrix}$ and $B'=\begin{bmatrix}-1 & 1\\0& 2\end{bmatrix},$ then $(A+2B)'$=
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\begin{bmatrix}-4 & 5\\1 & 6\end{bmatrix}$
$A=\begin{pmatrix}-2 & 1\\3& 2\end{pmatrix}$ and $B'=\begin{bmatrix}-1 & 1\\0& 2\end{bmatrix}$
$A+2B=\begin{pmatrix}-4 & 1\\5& 6\end{pmatrix}$
$(A+2B)'=\begin{pmatrix}-4 & 5\\1 & 6\end{pmatrix}$