The value of $\frac{\sec ^6 \theta-\tan ^6 \theta-3 \sec ^2 \theta \tan ^2 \theta+1}{\cos ^4 \theta-\sin ^4 \theta+2 \sin ^2 \theta+2}$ is :
Answer & explanation
Correct answer: option 3
A detailed explanation for this question is coming soon.
The value of $\frac{\sec ^6 \theta-\tan ^6 \theta-3 \sec ^2 \theta \tan ^2 \theta+1}{\cos ^4 \theta-\sin ^4 \theta+2 \sin ^2 \theta+2}$ is :
Correct answer: option 3
A detailed explanation for this question is coming soon.