The area enclosed between the curves $y = x$ and $y=2x-x^2$ (in square units), is
Answer & explanation
Correct answer: option 2
Clearly,
Shaded Area = $\int\limits_0^1\{(2x-x^2)-x\}dx$
⇒ Shaded Area = $\int\limits_0^1(x-x^2)dx=\left[\frac{x^2}{2}-\frac{x^3}{3}\right]_0^1=\frac{1}{6}$
