Tickets numbered from 1 to 20 are mixed and a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3?
Answer & explanation
Correct answer: option 1
Tickets numbered from 1 to 20 are
= 1 , 2 , 3 , 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 ,15, 16 ,17, 18, 19, 20
number which is a multiple of 3 = 3 , 6 , 9 , 12 , 15 , 18
The probability that the ticket drawn bears a number which is a multiple of 3
= \(\frac{6}{20}\)
= \(\frac{3}{10}\)