Tickets numbered from 1 to 20 are mixed and a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3?

$\frac{3}{10}$

Tickets numbered from 1 to 20 are

= 1 , 2 , 3 , 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 ,15, 16 ,17, 18, 19, 20

number which is a multiple of 3 = 3 , 6 , 9 , 12 , 15 , 18

The probability that the ticket drawn bears a number which is a multiple of 3

= \(\frac{6}{20}\)

= \(\frac{3}{10}\)