Tickets numbered from 1 to 20 are mixed and a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \(\frac{3}{10}\)
Probability = favourable outcomes ÷ total outcomes, as every ticket is equally likely to be drawn.
Total outcomes: any of the 20 tickets
Multiples of 3 up to 20: 3, 6, 9, 12, 15, 18, that is, 6 tickets
Probability of a multiple of 3 \(=\frac{6}{20}=\frac{3}{10}\)