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CUET
General Test
Quantitative Reasoning
Permutation
For which value of the k, the pair of linear equations has no solution $6x-3y+10=0$ and $kx-y+9=0$:
1
-1
2
-2
6x−3y+10 = 0
kx−y+9 = 0
Here, a1 = 6,
b1 = −3,
c1 = 10
a2 = k,
b2 = −1,
c2 = 9
We know that,
a1/a2 = b1/b2
6/k = -3/-1
k = 2