Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Permutation

Question:

For which value of the k, the pair of linear equations has no solution $6x-3y+10=0$ and $kx-y+9=0$:

Options:

1

-1

2

-2

Correct Answer:

2

Explanation:

6x−3y+10 = 0

kx−y+9 = 0

Here, a1 = 6,

b1 = −3,

c1 = 10

a2 = k,

b2 = −1,

c2 = 9

We know that,

a1/a2 = b1/b2 

 6/k = -3/-1

k = 2