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For which value of the k, the pair of linear equations has no solution $6x-3y+10=0$ and $kx-y+9=0$: |
1 -1 2 -2 |
2 |
6x−3y+10 = 0 kx−y+9 = 0 Here, a1 = 6, b1 = −3, c1 = 10 a2 = k, b2 = −1, c2 = 9 We know that, a1/a2 = b1/b2 6/k = -3/-1 k = 2 |
