The ratio of milk to water in a 100 litres mixture is 2 : 3. 10 litres of this mixture is withdrawn and replaced with milk. This process is repeated 2 more times, what is the % of milk in final mixture? |
56.26% 43.74% 58.21% 41.79% |
56.26% |
Total initial mixture = 100 liter Ratio of Milk and Water = 2 : 3 Water qty. = 100 ×\(\frac{3}{5}\) ATQ, Part replaced = \(\frac{10}{100}\) = \(\frac{1}{10}\) Remaining Qty of Water = \(\frac{9}{10}\) = \(\frac{Water}{Mixture}\) Process repeated 2 times more, Therefore, Water in final mixture = 100 × \(\frac{3}{5}\) × \(\frac{9}{10}\)× \(\frac{9}{10}\) × \(\frac{9}{10}\) = 43.74 Hence Milk in final mixture = 100 - 43.74 = 56.26
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