The ratio of milk to water in a 100 litres mixture is 2 : 3. 10 litres of this mixture is withdrawn and replaced with milk. This process is repeated 2 more times, what is the % of milk in final mixture?

56.26%

Total initial mixture = 100 liter

Ratio of Milk and Water = 2 : 3

Water qty. = 100 ×\(\frac{3}{5}\)

ATQ,

Part replaced = \(\frac{10}{100}\) = \(\frac{1}{10}\)

Remaining Qty of Water = \(\frac{9}{10}\) = \(\frac{Water}{Mixture}\)

Process repeated 2 times more,

Therefore,

Water in final mixture = 100 × \(\frac{3}{5}\) × \(\frac{9}{10}\)× \(\frac{9}{10}\) × \(\frac{9}{10}\)

= 43.74

Hence Milk in final mixture = 100 - 43.74 = 56.26

Alternate: