The ratio of milk to water in a 100 litres mixture is 2 : 3. 10 litres of this mixture is withdrawn and replaced with milk. This process is repeated 2 more times, what is the % of milk in final mixture?
Answer & explanation
Correct answer: option 1
Total initial mixture = 100 liter
Ratio of Milk and Water = 2 : 3
Water qty. = 100 ×\(\frac{3}{5}\)
ATQ,
Part replaced = \(\frac{10}{100}\) = \(\frac{1}{10}\)
Remaining Qty of Water = \(\frac{9}{10}\) = \(\frac{Water}{Mixture}\)
Process repeated 2 times more,
Therefore,
Water in final mixture = 100 × \(\frac{3}{5}\) × \(\frac{9}{10}\)× \(\frac{9}{10}\) × \(\frac{9}{10}\)
= 43.74
Hence Milk in final mixture = 100 - 43.74 = 56.26
Alternate:
