ABCD is a cyclic quadrilateral. The tangents to the circle at the points A and C on it, intersect at P. If ∠ABC = 98°, then what is the measure of ∠APC?

22° 26° 16° 14°

16°

\(\angle\)APC = 180 - 2\(\angle\) = 180 - 2 x 82 = \({16}^\circ\). Therefore, \(\angle\)APC is \({16}^\circ\).