CUET Preparation Today
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a b c d |
b |
$\text{ Potential difference developed across the loop when it is pulled out of magnetic field is } \xi = Blv$ $\text{Power developed across the loop is }P = \frac{\xi^2}{R} = \frac{B^2l^2v^2}{R}$ $\Rightarrow P \propto v^2$ Correct graph is b |
