Rahul and Mithun travel a distance of 30 km. The sum of their speeds is 70 km/h and the total time taken by both to travel the distance is 2 hours 6 minutes. The difference between their speeds is:

30 km/h

Total time = 2 hours 6 minutes = \(\frac{21 }{10}\) hours

Let speed of Rahul = a km/h & Speed of Mithun = ( 70 - a ) km/h

Using formula :- Time = \(\frac{Distance }{Speed}\)

ATQ,

\(\frac{30 }{a}\) + \(\frac{30 }{70 - a }\) = \(\frac{21 }{10}\) hours 

\(\frac{10 }{a}\) + \(\frac{10 }{70 - a }\) = \(\frac{7 }{10}\)

 a² - 70a + 1000 = 0

On solving ,  a = is either 50 km/h or 20 km/h

SO , Difference b/w their speed = 50 - 20 = 30 km/h