6 men and 8 women can do a piece of work in 10 days, whereas 26 men and 48 women can do the same work in 2 days. What will be the time taken by 15 men and 20 women to do the same work?
Answer & explanation
Correct answer: option 3
6M + 8W = 10D
60M + 80W = 01D ..(1) (Multiplied by 10 to get it in 1 day)
26M + 48W = 2D
52M + 96W = 01D ..(2) (Multiplied by 2 to get it in 1 day)
NOW, (1) - (2), WE GET
⇒ 8M = 16W
⇒ M : W = 16 : 8 = 2 : 1 (Efficiencies)
Putting efficiency in equation (1), and get the total work
⇒ [60(2) + 80(1)]
⇒ 200
Now, total efficiency of 15M + 20W = 15(2) + 20(1) = 50
Required time = \(\frac{Total work}{Efficiency}\) = \(\frac{200}{50}\) = 4 days