Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Algebra

Question:

$∫sin^3x\, dx$ is equal to :

Options:

$\frac{cos^3x}{3}+cos\, x+C$

$\frac{cos^3x}{3}-cos\, x+C$

$\frac{cos^2x}{3}-cos\, x+C$

$\frac{sin^3x}{3}+sin\, x+C$

Correct Answer:

$\frac{cos^3x}{3}-cos\, x+C$