Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

Options:

$13.6 eV$

$+\frac{13.6}{9} eV$

$-\frac{13.6}{3} eV$

$-\frac{3}{13.6} eV$

Correct Answer:

$+\frac{13.6}{9} eV$

Explanation:

Energy required to knock out the electron in the nth orbit $=+\frac{13.6}{n^2} eV \Rightarrow$ $E_3=+\frac{13.6}{9} eV$