A and B together can do a piece of work in 24 days. A alone can do this work in 40 days. In how many days can B alone do this work?
Answer & explanation
Correct answer: option 3
A + B = 24 days, A = 40 days,
⇒ A + B = 5 (Efficiency)
⇒ 3 + B = 5,
⇒ B = 2,
⇒ Therefore, time required for B to complete total work is = \(\frac{120}{2}\) = 60 days. ..(\(\frac{Work}{Efficiency}\) = Time)