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In the given figure, DE ∥ BC. If AD = 5 cm, DB = 10 cm, and AE = 8 cm, then AC is:
|
24 cm 32 cm 8 cm 16 cm |
24 cm |
In the given diagram, DE is parallel to BC = So, \(\frac{AD}{DB}\) = \(\frac{AE}{EC}\) = \(\frac{5}{10}\) = \(\frac{8}{EC}\) = EC = \(\frac{8\;×\;10}{5}\) = 8 × 2 = 16 = AC = AE + EC = 8 + 16 = 24 cm Therefore, AC is 24 cm. |
