In the given figure, DE ∥ BC. If AD = 5 cm, DB = 10 cm, and AE = 8 cm, then AC is:
Answer & explanation
Correct answer: option 1
In the given diagram,
DE is parallel to BC
= So, \(\frac{AD}{DB}\) = \(\frac{AE}{EC}\)
= \(\frac{5}{10}\) = \(\frac{8}{EC}\)
= EC = \(\frac{8\;×\;10}{5}\) = 8 × 2 = 16
= AC = AE + EC = 8 + 16 = 24 cm
Therefore, AC is 24 cm.