If $\frac{2 p}{p^2-5 p+1}=\frac{1}{10}, p \neq 0$, then the value of $\left(p+\frac{1}{p}\right)$ is:

10 25 1 15

25

$\frac{2 p}{p^2-5 p+1}=\frac{1}{10}, p \neq 0$ = 20p = p2 - 5 p + 1 = p2 - 5 p + 1 = 20p =  p2 - 25 p + 1 = 0 Divide by p on both sides =  p + \(\frac{1}{p}\) = 25