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If $\frac{2 p}{p^2-5 p+1}=\frac{1}{10}, p \neq 0$, then the value of $\left(p+\frac{1}{p}\right)$ is: |
10 25 1 15 |
25 |
$\frac{2 p}{p^2-5 p+1}=\frac{1}{10}, p \neq 0$ = 20p = p2 - 5 p + 1 = p2 - 5 p + 1 = 20p = p2 - 25 p + 1 = 0 Divide by p on both sides = p + \(\frac{1}{p}\) = 25 |
