If $\frac{2 p}{p^2-5 p+1}=\frac{1}{10}, p \neq 0$, then the value of $\left(p+\frac{1}{p}\right)$ is:
Answer & explanation
Correct answer: option 2
$\frac{2 p}{p^2-5 p+1}=\frac{1}{10}, p \neq 0$
= 20p = p2 - 5 p + 1
= p2 - 5 p + 1 = 20p
= p2 - 25 p + 1 = 0
Divide by p on both sides =
p + \(\frac{1}{p}\) = 25