Answer & explanation
Correct answer: option 4
$\text{The Current Gain is }\beta = \frac{\Delta I_C}{\Delta I_B}= \frac{5 mA}{50\mu A} = 100$
Correct answer: option 4
$\text{The Current Gain is }\beta = \frac{\Delta I_C}{\Delta I_B}= \frac{5 mA}{50\mu A} = 100$