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Home Questions YM4SEMVHC5

Target Exam

CUET

Subject

Physics

Chapter

Semiconductors and Electronic Devices

Question:

Options:

a

b

c

d

Correct Answer:

d

Explanation:

$\text{The Current Gain is }\beta = \frac{\Delta I_C}{\Delta I_B}= \frac{5 mA}{50\mu A} = 100$

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