Consider the given graph between the stopping potential and frequency of incident light in an experiment of photoelectric effect. The slope of the graph gives:

(where symbols have their used meanings)

$\frac{h}{e}$

The correct answer is option (2) : $\frac{h}{e}$

$eV_0=hf-\phi_0, \begin{matrix}V_0 \to \text{Stopping potential}\\\phi_0 \to \text{Work function }\end{matrix}$

$⇒V_0=\left(\frac{h}{e}\right)f-\phi_0$

⇒ Slope of graph obtained is $\frac{h}{e}$