If the diagonals of a rhombus are 10 cm and 24 cm, then what is the perimeter of the rhombus?

52 cm

= Diagonals of rhombus intersect each other at the angle of 90 degrees.

= \( {OD }^{2 } \) + \( {OA }^{2 } \) = \( {AD }^{ 2} \)

= \( {5 }^{2 } \) + \( {12 }^{ 2} \) = \( {AD }^{ 2} \)

= 25 + 144 = \( {AD }^{2 } \)

= \( {AD }^{2 } \) = 169

= AD = 13 cm

The perimeter of rhombus = 4 x 13 = 52 cm

Therefore, Perimeter of rhombus is 52 cm.