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CUET
General Test
Quantitative Reasoning
Algebra
If 4√3x2+5x−2√3=(Ax+2)(Bx+C), then what is the value of (A + B + C) ? (A > 0) |
4 4+√3 2√3 4−√3 |
4 |
Given, 4√3 x2 + 5x – 2√3 = (Ax + 2)(Bx + C) According to the question, 4√3 x2 + 5x – 2√3 = 4√3x2 + 8x – 3x – 2√3 = 4x(√3 x + 2) – √3 (√3 x + 2) = (√3 x + 2) (4x – √3) Now, ⇒ A = √3, B = 4 and C = -√3 (A + B + C) = (√3 + 4 + (-√3) = (√3 + 4 – √3) = 4 |