Find the area of four walls of a room having length 12.5 m, breadth 9 m and height 7 m.
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 301 m2
The four walls of a room, opened out, make one long rectangle whose length is the perimeter of the floor and whose height is the height of the room. So the area of four walls \(=2h(l+b)\); the floor and the ceiling are not included.
Perimeter of the floor \(=2(12.5+9)=43\) m
Area of four walls \(=43\times7=301\,\mathrm{m^2}\)