The amount of urea required to make a 500 mL solution of 0.25 molarity is

(Molar mass of Urea = $60\, g\, mol^{-1}$)

7.5 g

The correct answer is Option (1) → 7.5 g

We can calculate the mass of urea required using the formula:

$\text{Mass} = M \times V \times \text{Molar mass}$

Where:

• $M = 0.25 \, \text{mol/L}$
• $V = 0.5 \, \text{L}$ (since 500 mL = 0.5 L)
• $\text{Molar mass of urea} = 60 \, \text{g/mol}$

$\text{Mass} = 0.25 \times 0.5 \times 60 = 7.5 \, \text{g}$