Match List - I with List - II.
|
List - I (Polymer) |
List – II (Monomer) |
|
(A) Nylon 2-nylon 6 |
(I) Ethylene glycol and Benzene-1,2-dicarboxylic acid |
|
(B) Neoprene |
(II) Glycine and Amino caproic acid |
|
(C) Glyptal |
(III) Adipic acid and Hexamethylene diamine |
|
(D) Nylon 6, 6 |
(IV) 2-chlorobuta-1,3-diene |
Choose the correct answer from the options given below :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
A polymer is made from its monomers. Condensation polymers (the nylons, glyptal) come from two monomers that lose water as they join; neoprene is an addition polymer of one monomer.
(A) Nylon 2-nylon 6 — This matches (II) Glycine and Amino caproic acid. It is an alternating copolyamide of glycine (two carbons) and ε-aminocaproic acid (six carbons), and it is biodegradable.
\( n\,\ce{H2N-CH2-COOH} + n\,\ce{H2N-(CH2)5-COOH} \rightarrow \ce{-[NH-CH2-CO-NH-(CH2)5-CO]_{n}-} + (2n-1)\,\ce{H2O} \)
(B) Neoprene — This matches (IV) 2-chlorobuta-1,3-diene. Free radical polymerisation of chloroprene gives polychloroprene (neoprene), a synthetic rubber.
\( n\,\ce{CH2=C(Cl)-CH=CH2} \rightarrow \ce{-[CH2-C(Cl)=CH-CH2]_{n}-} \)
(C) Glyptal — This matches (I) Ethylene glycol and Benzene-1,2-dicarboxylic acid. Ethane-1,2-diol and phthalic acid condense to a polyester used in paints and lacquers.
\( n\,\ce{HOCH2CH2OH} + n\,\ce{C6H4(COOH)2} \rightarrow \ce{-[OCH2CH2O-CO-C6H4-CO]_{n}-} + (2n-1)\,\ce{H2O} \)
(D) Nylon 6, 6 — This matches (III) Adipic acid and Hexamethylene diamine. Both monomers have six carbon atoms, hence the name 6,6.
\( n\,\ce{H2N(CH2)6NH2} + n\,\ce{HOOC(CH2)4COOH} \rightarrow \ce{-[NH(CH2)6NH-CO(CH2)4CO]_{n}-} + (2n-1)\,\ce{H2O} \)
Note: This question is from the pre-rationalised NCERT book (2022-23). The topic is not there in the latest NCERT book (2026-27), and it is also out of the CUET 2026 syllabus.