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M is the circumcentre of ΔABC with circumradius 15 cm. Let BC = 24 cm and ML is perpendicular to BC. Then the length of ML is : |
10 cm 12 cm 9 cm 8 cm |
9 cm |
In ΔABC AM = BM = CM = 15 (circumradius) We know that, BL = LC = 24/2 = 12 cm In right angled ΔMLC, (MC)2 = (ML)2 + (LC)2 = 152 = ML2 + 122 = ML2 = 225 - 144 = ML = \(\sqrt {81}\) = 9 cm |
