CUET Preparation Today
The shortest wavelength present in the Lyman series of spectral lines is: (Given Rydbage constant $R=1.097 \times 10^7 m^{-1}$ ) |
$9.1 \times 10^{-8} m$ $1.2 \times 10^{-7} m$ $8.2 \times 10^7 m$ $9.1 \times 10^8 m$ |
$9.1 \times 10^{-8} m$ |
The correct answer is Option (1) → $9.1 \times 10^{-8} m$ |
