Answer & explanation
Correct answer: option 1
Combine power of lens is
P = $P_1+P_2$ = 1 D
Focal length of the combination = $\frac{100(cm)}{P}$ = 100 cm.
since focal length is positive so its a converging lens of focal length 100cm.
Correct answer: option 1
Combine power of lens is
P = $P_1+P_2$ = 1 D
Focal length of the combination = $\frac{100(cm)}{P}$ = 100 cm.
since focal length is positive so its a converging lens of focal length 100cm.