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In ΔPQR, QT ⊥ PR and S is a point on QR such that ∠PSQ = x°, ∠TQR = 38° and ∠SPR = 40°, then the value of x is? |
50 92 78 62 |
92 |
∠POT = 180° - (90° + 40°) = 50° In ΔPTQ ∠POT = ∠QOS = 50° (opposite angle) ∠PSQ = x° = 180° - (50° + 38°) = 92°
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