The ratio maximum wavelength to minimum wavelength in Lyman series is:

The correct answer is Option (1) → $\frac{4}{3}$

Using Rydberg formula,

$\frac{1}{λ}=R_H\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)$

for Lyman series, $n_1=1$

$\frac{1}{λ_{max}}=R_H\left(1-\frac{1}{4}\right)=\frac{3R_H}{4}$

$⇒λ_{max}=\frac{3R_H}{4}$

and,

$\frac{1}{λ_{min}}=R_H(1-0)$

$⇒λ_{min}=\frac{1}{R_H}$

$⇒\frac{λ_{max}}{λ_{min}}=\frac{4}{3}$