$\int\left(\sqrt{x}-\frac{1}{\sqrt{x}}\right)^2 d x$ is equal to
Answer & explanation
Correct answer: option 4
$\int\left(\sqrt{x}-\frac{1}{\sqrt{x}}\right)^2 d x=\int\left(x+\frac{1}{x}-2\right) d x=\frac{x^2}{2}+\ln |x|-2 x+c$
Hence (4) is the correct answer.