Three capacitors C1, C2 and C3 are connected to a 6 V battery, as shown in figure. The charge on the capacitor C1 is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 24 µC
$R_{23}=R_2+R_3$ [In series]
$R_{23}=4+4=8µF$
Now,
$\frac{1}{C_{eq}}=\frac{1}{8}+\frac{1}{8}$ [In parallel]
$⇒C_{eq}=4µF$
Charge (Q) = CV
$=4×6=24µC$
and,
Charge will be same in both the capacitor.
$∴C_1=24µC$