Three capacitors C₁, C₂ and C₃ are connected to a 6 V battery, as shown in figure. The charge on the capacitor C₁ is:

24 µC

The correct answer is Option (2) → 24 µC

$R_{23}=R_2+R_3$ [In series]

$R_{23}=4+4=8µF$

Now, 

$\frac{1}{C_{eq}}=\frac{1}{8}+\frac{1}{8}$ [In parallel]

$⇒C_{eq}=4µF$

Charge (Q) = CV

$=4×6=24µC$

and,

Charge will be same in both the capacitor.

$∴C_1=24µC$