Two circles touch each other externally at P. AB is a direct common tangent to the two circles, A and B are points of contact, and ∠PAB = 40°. The measure of ∠ABP is:
Answer & explanation
Correct answer: option 3
According to the concept, \(\angle\)APB = \({90}^\circ\)
Considering \(\Delta \)APB
\(\angle\)APB
⇒ \({90}^\circ\) - \(\angle\)PAB
⇒ \({90}^\circ\) - \({40}^\circ\) = \({50}^\circ\)
Therefore, \(\angle\)APB is \({50}^\circ\)