Practicing Success
Case : Read the passage and answer the question(s). In a parallel plate air capacitor having plate separation 0.05mm, an electric field of 4X104 V/m is established between the plates. After the removal of the battery a metal plate of thickness t = 0.02 mm is inserted between the plates of the capacitor. |
What is the potential difference across capacitor if dielectric slab with dielectric constant K=3 and same thickness were inserted in place of metal plate? |
1535 V 1500 V 1452 V 1466 V |
1466 V |
C' = \(\frac{\epsilon_{o} A}{d - t(1-1/k)}\) k = 3 ; d = 0.05 mm ; t = 0.02 mm C' = \(\frac{\epsilon_{o} A}{0.05)}\) \(\frac{15}{11}\) Q is constant ∴ C' V' = C V V = E x d E = 4X104 V/m ; d = 0.05mm V = 2000 V V' = 1467.67 V |