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CUET
General Test
Numerical Ability
Percentages
A is 40% less than B, and C is 40% of the sum of A and B. The difference between A and B is what percentage of C?
60.5%
64%
62.5%
60%
Let the value of B be 100.Value of A = 100 × \(\frac{60}{100}\) = 60Value of C = (60 + 100) × \(\frac{40}{100}\) = 64
Required difference = [ \(\frac{100-60}{64}\)] × 100 = 62.5%