ABC is an isosceles triangle in which AB = BC, AD is angle bisector of ∠BAC. Find the value of β?
Answer & explanation
Correct answer: option 3
5α + α + 3θ +\(\frac{3θ}{2}\) + \(\frac{3θ}{2}\) = 180°
6α + 6θ = 180°
α + θ = 30°
α + θ = β = 30°
ABC is an isosceles triangle in which AB = BC, AD is angle bisector of ∠BAC. Find the value of β?
Correct answer: option 3
5α + α + 3θ +\(\frac{3θ}{2}\) + \(\frac{3θ}{2}\) = 180°
6α + 6θ = 180°
α + θ = 30°
α + θ = β = 30°