Practicing Success
The maximum area of the rectangle whose sides pass through the angular points of a given the rectangle is of sides a and b is |
$(\frac{1}{2})(ab)^2$ $(\frac{1}{2})(a+b)$ $(\frac{1}{2})(a+b)^2$ none of these |
$(\frac{1}{2})(a+b)^2$ |
Let ABCD be the given rectangle of sides a and b and EFGH be any rectangle, whose sides pass through A, B, C, D. A = area EFGH $= (b\sin θ+ a\cos θ) (a\sin θ+b\cos θ)$ $= ab+ (a^2 + b^2)\sin θ\cos θ$ $\frac{dA}{dθ}=(a^2 + b^2)\cos 2θ$ so $\frac{dA}{dθ}=0⇒θ=\frac{π}{4}$ $⇒\frac{d^2A}{dθ^2}=-(a^2 + b^2)\sin 2θ$; so $\frac{d^2A}{dθ^2}|_{θ=\frac{π}{4}}<0$ Hence $A_{max}=(\frac{1}{2})(a+b)^2$ |