Study the adjoining picture and answer the following questions:
Area of ΔAFC is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 125 m2
The area of a triangle is \(\frac{1}{2}\times\text{base}\times\text{height}\), where the height is the perpendicular from the third vertex to the base. In ΔAFC, take AC as the base; FB is drawn at right angles to AC, so FB is the height.
Base AC \(=25\) m and height BF \(=10\) m (from the figure)
Area \(\displaystyle =\frac{1}{2}\times25\times10=125\) m2