Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Work Power Energy

Question:

A particle of mass m is driven by a machine that delivers a constant power k watts. If the particle starts from rest the force on the particle at time t is :

Options:

\(\sqrt{\frac{mk}{t}}\)

\(\sqrt{\frac{2mk}{t}}\)

\(\frac{1}{2}\sqrt{\frac{mk}{t}}\)

\(\sqrt{\frac{mk}{2t}}\)

Correct Answer:

\(\sqrt{\frac{mk}{2t}}\)

Explanation:

P = Fv = v.ma

K = mv \(\frac{dv}{dt}\)

On integrating : v = \(\sqrt{\frac{2kt}{m}}\)

a = \(\frac{dv}{dt}\) = \(\sqrt{\frac{2kt}{m}} \frac{1}{2\sqrt{t}}\)

F = \(\sqrt{\frac{mk}{2t}}\)