Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Work Power Energy

Question:

The energy that will be ideally radiated by a 100 kW transmitter in 1 hour is : 

Options:

36 x 107 J

36 x 10J

36 x 105 J

1 x 105 J

Correct Answer:

36 x 107 J

Explanation:

Energy : E = P t

Power : P = 100 kW ; Time : t = 1 hr = 3600 s

E = 36 x 107 J