A wire is stretched to increase its length by 4 times. The resistance of the wire will: |
decrease by 4 times increase by 4 times increase by 8 times increase by 16 times |
increase by 16 times |
The correct answer is Option (4) → increase by 16 times The resistance (R) is $R=ρ\frac{L}{A}$ $R'=ρ\frac{4L}{A/4}=16ρ\frac{L}{A}$ $\frac{R}{R'}=\frac{1}{16}$ |