If cos B = $\frac{5}{7}$, what is the value of cosec B + cot B ? Given that 0 < B < $\frac{\pi}{2}$

$\frac{5}{\sqrt{6}}$ $\frac{\sqrt{6}}{12}$ $\frac{7}{\sqrt{6}}$ $\sqrt{6}$

$\sqrt{6}$

cosB = \(\frac{5}{7}\)  By using pythagoras theorem , P2 + B2 = H2 P2 + 52 = 72 P = 2√6 Now , cosec B + cot B = \(\frac{7}{2√6 }\) + \(\frac{5}{2√6 }\) = \(\frac{12}{2√6 }\) = √6