The area of region bounded by the curve $y=x+1$ and he lines $x=2$ and $x=3$ is

$\frac{7}{2}$ sq.units

The correct answer is Option (1) → $\frac{7}{2}$ sq.units

Area Bounded = $\int\limits_2^3 x+1\,dx$

$=\left[\frac{x^2}{2}+x\right]_2^3$

$=\left[\frac{9}{2}+3-\frac{4}{2}-2\right]$

$=\left[\frac{9}{2}-1\right]=\frac{7}{2}$ sq.units