If the four colours of the bands in a carbon resistor are orange, blu…

The correct answer is Option (4) → \( (36\times10^{4})\pm5\%\,\Omega \)

The colour code of a carbon resistor reads as follows: the first two bands give the first two digits, the third band gives the power-of-ten multiplier and the fourth band gives the tolerance.

    Orange = 3, Blue = 6 → digits 36
    Yellow = \( 10^{4} \) → multiplier
    Gold → tolerance \( \pm5\% \)

    \( R = 36\times10^{4}\,\Omega\ \pm5\% = 360\,\mathrm{k}\Omega\ \pm5\% \)

Note: This question is from the pre-rationalised NCERT book (2022-23). The topic was removed from the latest NCERT book (2026-27), and it also appears to be out of the CUET 2026 syllabus.

NCERT (Pre-rationalised edition, 2022-23):
Resistivity of Various Materials – “… The first two bands from the end indicate the first two significant figures of the resistance in ohms. The third band indicates the decimal multiplier (as listed in Table 3.2). The last band stands for tolerance or possible variation in percentage about the indicated values. … For example, if the four colours are orange, blue, yellow and gold, the resistance value is 36 × 10⁴ Ω, with a tolerence value of 5%.”