Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(A)-(I), (B)-(II), (C)-(III), (D)-(IV) |
The correct answer is Option (1) → (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
(A) Hinsberg's Test $\rightarrow$ (I) Primary, Secondary and Tertiary Amines: This test uses benzenesulfonyl chloride (Hinsberg reagent) to distinguish between the three classes of amines based on the solubility of their sulfonamide products in alkali.
(B) Isocyanide Test (Carbylamine Reaction) $\rightarrow$ (II) Aliphatic and Aromatic Primary Amines: Primary amines ($R-NH_2$), whether aliphatic or aromatic, react with chloroform and alcoholic $KOH$ to produce foul-smelling isocyanides (carbylamines). Secondary and tertiary amines do not show this reaction. (C) Azo Dye Test $\rightarrow$ (III) Primary Aromatic Amines: This test involves the formation of a diazonium salt followed by coupling with a phenol (like $\beta$-naphthol) to form a brightly colored azo dye. It is highly specific for primary aromatic amines like aniline. Aliphatic primary amines do not form stable diazonium salts at $0-5^\circ C$ and thus do not give this dye test. (D) Tollen's Test $\rightarrow$ (IV) Reducing Sugars: Tollen's reagent (ammoniacal silver nitrate) is used to detect aldehydes. Since all monosaccharides and many disaccharides (like maltose and lactose) act as reducing sugars because they contain or can form an aldehyde group, they give a positive "silver mirror" test. |